即有∠FBC=∠DBC，故可推知BC為∠FBE的角平分線，因此可得D為

即有∠FBC=∠DBC，故可推知BC為∠FBE的角平分線，因此可得D為△ABF的一個旁心，所以DF為∠BFC的角平分線，即∠=DFC45°，此時便可得知

ผลลัพธ์ (อังกฤษ) 1:

Indicates that the FBC= indicates that the DBC, you can infer BC indicates that the angular bisector of the FBE, so it can be d for ABF next to a heart, so DF indicates that the angular bisector of the BFC, which indicates that the =DFC45 °, at which point we will

ผลลัพธ์ (อังกฤษ) 2:

Ie ∠ FBC = ∠ DBC, it can be extrapolated to ∠ FBE BC angle bisector, so you can get a △ ABF D next to the heart, so as ∠ BFC DF angle bisector that ∠ = DFC45 °, this time will be aware of

ผลลัพธ์ (อังกฤษ) 3:

Namely has ∠fbc=∠dbc, therefore may infer that BC is the ∠fbe internal bisector, therefore may result in D is a △abf center of escribed circle, therefore DF is the ∠bfc internal bisector, namely ∠=dfc45°, can know at this time