此時由個位數為1可知b、e必其中一數為3、一數為7，故知ab×de≤×

此時由個位數為1可知b、e必其中一數為3、一數為7，故知ab×de≤×1753=901，故不合；(2分)

ผลลัพธ์ (อังกฤษ) 1:

By single digits for 1 b, e, ending one of number 3, number 7, knowing abxde ≤ x1753=901, it is not, (2)

ผลลัพธ์ (อังกฤษ) 2:

At this point we can see by the digit 1 b, e will be one of the number 3, a number of 7, refresher ab × de ≤ × 1753 = 901, so substandard; (2 points)

ผลลัพธ์ (อังกฤษ) 3:

At this time is 1 may know b and e to by the number in the units place a number is a 3 and number is 7, old friend ab×de≤×1753=901, therefore does not gather; (2 points)